4x^2+1060x-93800=0

Solution for 4x^2+1060x-93800=0 equation:

4x^2+1060x-93800=0

a = 4; b = 1060; c = -93800;
Δ = b2-4ac
Δ = 10602-4·4·(-93800)
Δ = 2624400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2624400}=1620$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1060)-1620}{2*4}=\frac{-2680}{8}
=-335
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1060)+1620}{2*4}=\frac{560}{8}
=70
$